MCQ
Which of the following would the optically active
- A$CH_2=C=CH_2$
- B
- ✓$CH_3-CH=C=CH-CH_3$
- D
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$\begin{array}{*{20}{c}}
{\,{C_2}{H_5}} \\
{|\,\,\,\,\,} \\
{C{H_3} - C - C{H_2}Cl} \\
{|\,\,\,\,\,} \\
{\,{C_2}{H_5}}
\end{array}$