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STD 11 - 4. Chemical bonding and molecular structure — NEET STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceNEETSTD 11 - 4. Chemical bonding and molecular structure4 Marks
MCQ
Which of the two ions from the list given below that have the geometry that is explained by the same hybridization of orbitals, $NO_2^-, NO_3^-,NH_2^- , NH_4^+ , SCN^-$ ?
  • ✓
    $NO_2^-$ and $NO_3^-$
  • B
    $NH_4^+$ and $NO_3^-$
  • C
    $SCN^-$ and $NH_2^-$
  • D
    $NO_2^-$ and $NH_2^-$
✓

Answer

Correct option: A.
$NO_2^-$ and $NO_3^-$
a
$N O_{2}^{-} \rightarrow s p^{2}$

$N O_{3}^{-} \rightarrow s p^{2}$

$N H_{2}^{+} \rightarrow s p^{3}$

$N H_{4} \rightarrow s p^{3}$

$S C N^{+} \rightarrow s p$

$N O_{2}^{-}$ and $N O_{3}^{-}$ both have the same hybridisation,

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