MCQ
Which one gives only one monosubstitution product on chlorination
- A$n-$ pentane
- ✓Neopentane
- CIsopentane
- Dn-butane
Replaceable hydrogen atoms are present only on $4$ primary carbon atoms. Hence, it gives only are monochloro Substituted product.
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$\begin{array}{*{20}{c}}
{C{H_3} - CH - C{H_2} - C{H_2} - CH - C{H_3}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,} \\
{\,\,OTs\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,OTs}
\end{array}\xrightarrow[{(ii)\,KOH}]{{(i)\mathop {\,S}\limits^ \ominus H\,(one\,\,equivalent)}}[X]$
$[X]$ will be :
$(i)$ In pure water
$(ii)$ In presence of $0.1\ M AgNO_3$
$(iii)$ In presence of $2\ M aq.$ solution of $KCN$
$(iv)$ In presence of $ 1\ M aq$. solution of $Ca(CN)_2$
$(v)$ In presence of $2\ M aq.$ solution of $NH_3$
(Assuming $100\%$ dissociation of $AgNO_3, KCN$ and $Ca(CN)_2)$ and complex formation with $NH_3$ and $CN^-$ will take place.