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Answer
b
$(b,c)$ $C{H_3} - \mathop {\mathop {{C^ * }}\limits_{|\,\,\,\,}^{|\,\,\,\,\,} }\limits_{Br}^{H\,\,\,} - \mathop {\mathop {CH\,\,}\limits_{|\,\,\,\,\,\,\,\,\,} }\limits_{C{H_3}} - C{H_3}$ and $C{H_3} - C{H_2} - \mathop {\mathop {{C^ * }}\limits_{|\,\,\,\,\,}^{|\,\,\,\,\,} }\limits_{Br}^{H\,\,} - C{H_3}$
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