- A$NaHS{O_4}$
- ✓$NaKS{O_4}$
- C${K_4}Fe{(CN)_6}$
- D$Mg(OH)Cl$
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Assertion $A:$ Metallic sodium dissolves in liquid ammonia giving a deep blue solution, which is paramagnetic.
Reason $R:$ The deep blue solution is due to the formation of amide.
In the light of the above statements, choose the correct answer from the options given below :
$(A)$ $2 CO ( g )+ O _2( g ) \rightarrow 2 CO _2( g ) \quad \Delta H _1^\theta=- x\,kJ\,mol { }^{-1}$
$(B)$ $C$ (graphite) $+ O _2$ (g) $\rightarrow CO _2$ (g) $\Delta H _2^\theta=- y\,kJ\,mol -1$ The $\Delta H ^\theta$ for the reaction $......$.$C ($ graphite $)+\frac{1}{2} O _2( g ) \rightarrow CO ( g )$ is



(image) $\xrightarrow[(273-278\,K)]{NaN{{O}_{2}}/HCl}X$ ${\mkern 1mu} \xrightarrow{{N,N\, - \,\dim ethyl\,\,aniline}}Y$
The structure of $'Y'$ would be