Download App

STD 12 - p -Block elements - ll — JEE STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceJEESTD 12 - p -Block elements - ll4 Marks
MCQ
Which one is the anhydride of $HCl{O_4}$
  • A
    $C{l_2}O$
  • B
    $Cl{O_2}$
  • C
    $C{l_2}{O_6}$
  • ✓
    $C{l_2}{O_7}$
✓

Answer

Correct option: D.
$C{l_2}{O_7}$
d
(d) $2HCl{O_4}\, \to \,{H_2}O + C{l_2}{O_7}$.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

JEE STD 11 Science question papers→Gujarat Board STD 11 Science question papers→Gujarat Board question paper generator→

Similar questions

$P^H$ of $10^{-3}\, M\, NaCl$ solution at $25\,^oC$ is
→
The entropy of a perfectly crystalline solid at absolute zero is
→
${K_{sp}}$ value of $Al\,{(OH)_3}$ and $Zn\,{(OH)_2}$ are $8.5 \times {10^{ - 23}}$ and $1.8 \times {10^{ - 14}}$ respectively. If $N{H_4}OH$ is added in a solution of $A{l^{3 + }}$ and $Z{n^{2 + }},$ which will precipitate earlier
→
Which of the following compound give diastereomers when treated with $Br_2$ in  $CCl_4$ ?
→
If in hydrogen $e^-$ jumps from $3^{rd}$ lymen line to Ist lymen line then obtained wavelength is
→
Which of the following is used to prepare medical instruments
→
$100 \,\,mL$ of $0.04\;N\;HCl$ aqueous solution is mixsed with $100\,\, mL$ of $0.02\,\, N\,\, NaOH$ solution. The $pH$ of the resulting solution is
→
$C{H_3}C \equiv CC{H_3}\mathop {\xrightarrow{{(i){\text{ }}X}}}\limits_{(ii){H_2}O/Zn}$

$\begin{array}{*{20}{c}}
  {C{H_3} - C - C - C{H_3}} \\ 
  {|\,\,\,\,\,\,\,\,\,\,\,\,|} \\ 
  {O\,\,\,\,\,\,\,\,\,O} 
\end{array}$  $X$ in the above reaction is

→
How many propenyl radical is possible from propene
→
The general formulas ${C_n}{H_{2n}}{O_2}$ could be for open chain
→