- A$0.015 M$ urea
- B$0.01\,M\,KN{O_3}$
- ✓$0.01\,M\,N{a_2}S{O_4}$
- D$0.015\,M\,$glucose
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$[X]$ $\xrightarrow{{KMn{O_4}/\mathop O\limits^\Theta H/\Delta }}$ $\begin{array}{*{20}{c}}
{\begin{array}{*{20}{c}}
{\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\
{HOOC - {{(C{H_2})}_3} - CH - COOH}
\end{array}}
\end{array}}
\end{array}$
$[X]$ will be:
| $t/s$ | $0$ | $30$ | $60$ | $90$ |
| $ Ester/$ $mol\,L^{-1}$ | $0.55$ | $0.31$ | $0.17$ | $0.085$ |
What will be the average rate of reaction between the time interval $30$ to $60\, seconds$ ?
$\mathop { - CH{{(C{H_3})}_2}}\limits_1 \,\,\,\,\,\,\,\,\,\,\,\mathop { - C{H_2}C{H_2}Br}\limits_2 \,\,\,\,\,\,\,\,\,\,\mathop{ - C{H_2}Br}\limits_3 \,\,\,\,\,\,\,\,\,\mathop{ - C{{(C{H_3})}_3}}\limits_4$
$I = II = III = IV$
