- A$0.015 M$ urea
- B$0.01\,M\,KN{O_3}$
- ✓$0.01\,M\,N{a_2}S{O_4}$
- D$0.015\,M\,$glucose
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$(a)$ $\begin{array}{*{20}{c}}
{C{H_3} - CH - Br} \\
{|\,\,} \\
{\,\,\,\,\,{C_2}{H_5}\,}
\end{array}$ $(b)$ $\begin{array}{*{20}{c}}
{\,\,Br\,} \\
{|\,} \\
{C{H_3} - C - C{H_3}} \\
{|\,} \\
{\,\,\,\,\,{C_2}{H_5}}
\end{array}$ $(c)$ $\begin{array}{*{20}{c}}
{{C_2}{H_5} - CH - C{H_2}Br} \\
{\,\,|\,\,\,\,\,\,\,\,\,\,\,} \\
{{C_2}{H_5}\,\,}
\end{array}$
$\frac{d[NH_3]}{dt} = 2 \times 10^{-4} \, mol \,L^{-1} \, s^{-1}$ , the value of $\frac{-d[H_2]}{dt}$ would be .................. $mol \,L^{-1} \, s^{-1}$
$A.$ Chlorophyll - Co
$B.$ Water hardness - EDTA
$C.$ Photography $-\left[ Ag ( CN )_2\right]^{-}$
$D.$ Wilkinson catalyst - $\left[\left(P h_3 P\right)_3 R h C l\right]$
$E.$ Chelating ligand - D - Penicillamine
Choose the correct answer from the options given below: