MCQ
Which one of the following metals will not reduce ${H_2}O$
- A$Ca$
- B$Fe$
- ✓$Cu$
- D$Li$
$E_{L{i^ + }/Li}^0 = - \,\,3.04\,\,V$ $E_{{H^ + }/{H_2}}^0 = 0.00\,V$
$E_{C{a^ + }/Ca}^0 = - 2.87\,V$ $E_{C{u^ + }/Cu}^0 = + 0.34\,V$
$Cu$ comes below $H$ in the electrochemical series.
Hence, unable to displace hydrogen from water.
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${C_6}{H_5}Cl + 2NaOH\mathop {\xrightarrow{{200 - {{250}\,^o}C}}}\limits_{200\,atm} {C_6}{H_5}ONa + NaCl + {H_2}O$

Given: $\Delta H ^0=-54.07\,kJ\,mol ^{-1}$
$\Delta S ^{\circ}=10\,JK ^{-1}\,mol ^{-1}$
(Take $2.303 \times 8.314 \times 298=5705$ )