MCQ
Which one of the following molecules is expected to exhibit diamagnetic behaviour ?
- ✓$C_2$
- B$F_2$
- C$O_2$
- D$S_2$
✓
Answer
Correct option: A.
$C_2$
a
$\pi 2 p_{x}^{2} \approx \pi 2 p_{y}^{2}$
$\pi 2 p_{x}^{2} \approx \pi 2 p_{y}^{2}$
Since, all the' electrons are paired, it is a diamagnetic specie. $\mathrm{N}_{2}(7+7=14)=\sigma 1 \mathrm{s}^{2},{ }^{\star} \mathrm{\sigma} \cdot 1 \mathrm{s}^{2}, \sigma 2 \mathrm{s}^{2}$
$\stackrel{*}{\sigma} 2 s^{2}, \pi 2 p_{x}^{2} \approx \pi 2 p_{y}^{2}, \sigma 2 p_{z}^{2}$
It is also a diamagnetic specie because of the absence of unpaired electrons.
$0_{2}(8+8=16)$
$\mathrm{Or} \quad \mathrm{S}_{2}=\sigma 1 \mathrm{s}^{2}, \stackrel{*}{\sigma} 1 \mathrm{s}^{2}, \sigma 2 \mathrm{s}^{2},{ }^{*} 2 \mathrm{s}^{2}$
$\sigma 2 p_{z}^{2}, \pi 2 p_{x}^{2} \approx \pi 2 p_{y}^{2}, \pi 2 p_{x}^{1} \approx \pi 2 p_{y}^{1}$
Since, $\mathrm{O}_{2}$ or $\mathrm{S}_{2}$ contain 2 unpaired electrons, therefore they are paramagnetic.
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