MCQ
Which one of the following molecules is paramagnetic?
- A$N_2$
- B$NO$
- ✓$CO$
- D$O_3$
Total no. of electrons in $NO$
$=7(N)+8(O)=15$
Hence $E.C.$ of $NO$
$KK{[\sigma 2s]^2}{[{\sigma ^*}(2s)]^2}{[\sigma 2{p_z}]^2}$
${[\pi (2{p_x})]^2}[\pi {(2{p_y})^2}]{[{\pi ^*}(2{p_x})]^1}$
Due to presence of one unpaired electron
$NO$ is paramagnetic.
Except $NO$ all are diamagnetic dur to absence of unpaired electrons.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
The above diagram represents: