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STD 11 - 8.2 Organic chemistry isomerism — JEE STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceJEESTD 11 - 8.2 Organic chemistry isomerism4 Marks
MCQ
Which one of the following shows optical activity
  • A
    $HO - \mathop {\mathop {\mathop {\mathop C\limits^| }\limits^H }\limits_| }\limits_H  - COOH$
  • ✓
    $C{H_3} - \mathop {\mathop {\mathop {\mathop C\limits^| }\limits^H }\limits_| }\limits_{Cl}  - COOH$
  • C
    $C{H_3} - \mathop {\mathop {\mathop {\mathop {C - \,}\limits^{|\,\,\,\,\,} }\limits^{C{H_3}} }\limits_{|\,\,\,\,\,\,} }\limits_{OH\,\,} COOH$
  • D
    $C{H_3} - \mathop {\mathop {\mathop {\mathop {C - \,}\limits^{|\,\,\,\,\,\,} }\limits^{C{H_3}} }\limits_{|\,\,\,\,\,\,} }\limits_{Cl\,\,\,} COOH$
✓

Answer

Correct option: B.
$C{H_3} - \mathop {\mathop {\mathop {\mathop C\limits^| }\limits^H }\limits_| }\limits_{Cl}  - COOH$
b
(b) $C{H_3} - \mathop {\mathop {\mathop {\mathop C\limits_| }\limits_{Cl} \,}\limits^{|*} }\limits^H - COOH$

In this structure chiral carbon atom is present since it is optical active.

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