MCQ
Which one will liberate $B{r_2}$ from $KBr$
- A${I_2}$
- B$S{O_2}$
- C$HI$
- ✓$C{l_2}$

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$(A)$ $\Lambda \stackrel{0}{ m }$ for electrolyte $A$ is obtained by extrapolation
$(B)$ For electrolyte B, vx $\Lambda m$ vs $\sqrt{ c }$ graph is a straight line with intercept equal to $\Lambda \stackrel{0}{ m }$
$(C)$ At infinite dilution, the value of degree of dissociation approach zero for electrolyte $B$.
$(D)$ $\Lambda \stackrel{0}{ m }$ for any electrolyte $A$ or $B$ can be calculated using $\lambda^{\circ}$ for individual ions.

Reason : Inert gases have stable configuration.