MCQ
Which orbit of $Be^{+3}$ has the same orbit radius as that of the ground state of hydrogen atom
- A$3$
- ✓$2$
- C$4$
- D$5$
$r =0.059 \frac{ n ^2}{ z } A$
Since for $Be , z =4$
$\frac{ n ^2}{4}=\frac{1^2}{1}$
Hence, $n=2$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
(Given : Molar Mass $\mathrm{Na}: 23$ and $\mathrm{Cl}: 35.5 \mathrm{gmol}^{-1}$ )
