MCQ
Which pair from the following will not form an ideal solution
- A$CC{l_4} + SiC{l_4}$
- ✓${H_2}O + {C_4}{H_9}OH$
- C${C_2}{H_5}Br + {C_2}{H_5}I$
- D${C_6}{H_{14}} + {C_7}{H_{16}}$
✓
Answer
Correct option: B.
${H_2}O + {C_4}{H_9}OH$
b
(b)${H_2}O$ and ${C_4}{H_9}OH$ do not form ideal solution because there is hydrogen bonding between ${H_2}O$ and ${C_4}{H_9}OH$.
(b)${H_2}O$ and ${C_4}{H_9}OH$ do not form ideal solution because there is hydrogen bonding between ${H_2}O$ and ${C_4}{H_9}OH$.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
The highest magnetic moment is shown by the transition metal ion with which of the following outermost electronic configuration?
Identify the correct statement regarding enzymes
$X-O-X$ linkage present in $[X = P/S/Cl/Mn]$
→$(a) P_2O_7^{4-}$ $(b) S_2O_5^{2-}$
$(c) S_2O_7^{2-}$ $(d) Cl_2O_7$
$(e) Mn_2O_7$ $(f) S_2O_8^{2-}$
Product $(B)$ is
→The freezing points of equimolar solutions of glucose, $KN{O_3}$ and $AlC{l_3}$ are in the order of
→Arrange in decreasing acidic strength
→$A.\,\,F -CH_2\,\,CH_2\,\,COOH$
$\begin{array}{*{20}{c}}
{B.\,\,Cl - CH - C{H_2} - COOH} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{\,\,Cl\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$
$C.\,\,F -CH_2 -COOH$
$D.\,\,Br -CH_2-CH_2 -COOH$
Correct answer is
Benzophenone can be converted into benzene using
Among the following which one does not act as an intermediate in Hofmann rearrangement
In the following reaction, the product$(s)$ formed is(are)
→$(A)$ $P$ (major) $(B)$ $Q$ (minor) $(C)$ $R$ (minor) $(D)$ $S$ (major)
The strongest acid among the following is :