MCQ
Which reactions involves a change in the electronpair geometry for the underlined geometry
  • $\underset{\raise0.3em\hbox{$\smash{\scriptscriptstyle-}$}}{B}{{F}_{3}}+{{F}^{-}}\to \underset{\raise0.3em\hbox{$\smash{\scriptscriptstyle-}$}}{B}F_{4}^{-}$
  • B
    $\underset{\raise0.3em\hbox{$\smash{\scriptscriptstyle-}$}}{N}{{H}_{3}}+{{H}^{+}}\to \underset{\raise0.3em\hbox{$\smash{\scriptscriptstyle-}$}}{N}H_{4}^{+}$
  • C
    $2\underset{\raise0.3em\hbox{$\smash{\scriptscriptstyle-}$}}{S}{{O}_{2}}+{{O}_{2}}\to 2\underset{\raise0.3em\hbox{$\smash{\scriptscriptstyle-}$}}{S}{{O}_{3}}$
  • D
    ${{H}_{2}}\underset{\raise0.3em\hbox{$\smash{\scriptscriptstyle-}$}}{O}+{{H}^{+}}\to {{H}_{3}}{{\underset{\raise0.3em\hbox{$\smash{\scriptscriptstyle-}$}}{O}}^{+}}$

Answer

Correct option: A.
$\underset{\raise0.3em\hbox{$\smash{\scriptscriptstyle-}$}}{B}{{F}_{3}}+{{F}^{-}}\to \underset{\raise0.3em\hbox{$\smash{\scriptscriptstyle-}$}}{B}F_{4}^{-}$
a
$B F _3+ F ^{-} \rightarrow BF_4^{-}$involves a change in the electron pair geometry for the underlined atom.

In $BF _3$, the electron pair geometry for $B$ atom is plane triangular.

In $BF _4^{-}$, the electron pair geometry for $B$ atom is tetrahedral.

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