- ASaturated vapours
- BIce
- CWater
- DVapours
Explanation:
In case of saturated vapors, when a certain quantity of heat is removed, the temperature increases. Hence, the specific heat is negative for saturated vapors.
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$CH _{3} OH (1)+\frac{3}{2} O _{2}( g ) \rightarrow CO _{2}( g )+2 H _{2} O (1)$
the amount of heat produced as measured by bomb calorimeter is $726 \,kJ\, mol ^{-1}$ at $27^{\circ} C$. The enthalpy of combustion for the reaction is $- x \,kJ\,mol ^{-1}$, where $x$ is $.....$ (Nearest integer)
$\left(\right.$ Given $: R =8.3\, J\,K ^{-1} \,mol ^{-1}$ )
$\mathrm{H}_2(\mathrm{~g})+\mathrm{I}_2(\mathrm{~g}) \rightleftharpoons 2 \mathrm{HI}(\mathrm{g})$, the $\mathrm{K}_{\mathrm{p}}$ for the process is $\mathrm{x} \times 10^{-1} \cdot \mathrm{x}=$ $\qquad$
[Given : $\mathrm{R}=0.082 \mathrm{~L} \mathrm{~atm} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}$ ]