MCQ
Which statement is incorrect in respect of the above reaction ?


- AProduct is aromatic
- BProduct has high dipole moment
- ✓Product has less resonance energy
- DProduct is soluble in polar solvent


Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
| Peptide | $R _1$ | $R _2$ |
| $I$ | $H$ | $H$ |
| $II$ | $H$ | $CH _3$ |
| $III$ | $CH _2 COOH$ | $H$ |
| $IV$ | $CH _2 CONH _2$ | $( CH _2)_4 NH _2$ |
| $V$ | $CH _2 CONH _2$ | $CH _2 CONH _2$ |
| $VI$ | $( CH _2)_4 NH _2$ | $( CH _2)_4 NH _2$ |
| $VII$ | $CH _2 COOH$ | $CH _2 CONH _2$ |
| $VIII$ | $CH _2 OH$ | $( CH _2)_4 NH _2$ |
| $IX$ | $( CH _2)_4 NH _2$ | $CH _3$ |

$Toluene\,\, \xrightarrow[{2.\,{H^ + }}]{{1.\,KMn{O_4}/O{H^ - }}}I\xrightarrow{{SOC{l_2}}}II\xrightarrow{{N{H_3}}}III\xrightarrow{{OB{r^ - }}}IV$ is
$\underset{I}{\mathop{C{{H}_{3}}-C{{H}_{2}}-N{{H}_{2}}}}\,$
$\underset{II}{\mathop{{{(C{{H}_{3}}C{{H}_{2}})}_{2}}NH}}\,$
$\mathop {{{(C{H_3}C{H_2})}_3}N}\limits_{II} $

here $‘X’$ is :