- A$'NO-$ ligand' acts as cationic ligand.
- B$'Fe'$ present in $+2$ oxidation state
- ✓It's used to give test of $S^{-2}$ ion
- DAll of the above are correct
$Z =$ Atomic number of the metal
$X =$ Number of electrons lost during the formation of the metal ion from its atom
$Y =$ Number of electrons donated by the ligands
$EAN = Z - X + Y$
$36=26-2+Y$
$Y =12$
Hence, the number of monodentate ligand in this complex are $\frac{12}{2}=6$.
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Statement $I$ : Bromination of phenol in solvent with low polarity such as $\mathrm{CHCl}_3$ or $\mathrm{CS}_2$ requires Lewis acid catalyst.
Statement $II$ : The lewis acid catalyst polarises the bromine to generate $\mathrm{Br}^{+}$.
In the light of the above statements, choose the correct answer from the options given below :
Product will be
${N_2}{O_4}(g)\, \to \,2N{O_2}(g)$
Data for the given reaction is
$\Delta H = +54\,kJ$ and $E_a = + 57.2\,kJ$
.......$kJ$