Gujarat BoardEnglish MediumSTD 11 CommerceStatisticsGeometric progression3 Marks
Question
Which term of the $GP. 0.008, 0.016, 0.032,$ is $4.096$ ?
✓
Answer
Here, the first term $a=0.008$ and the common ratio $r=\frac{0.016}{0.008}=2$
Now, $\mathrm{T}_{n}=4.096$
$\therefore a r^{n-1}=4.096$
$\therefore 0.008 \times(2)^{n-1}=4.096$
$\therefore 2^{n-1}=\frac{4.096}{0.008}$
$\therefore 2^{n-1}=512$
$\therefore 2^{n-1}=2^{9}$
Equating the powers on both the sides, we get$ n-1=9$
$\therefore n=10$
Hence, $4.096$ is the $10\ th$ term of the given $G.P.$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.