Question
Which term of the sequence $24,\ 23\frac{1}{4},\ 22\frac{1}{2},\ 21\frac{3}{4}...$ is the first negative term?

Answer

The given sequence is $24,\ 23\frac{1}{4},\ 22\frac{1}{2},\ 21\frac{3}{4}...$
Here, $​​\text{a}=24$
$​​\text{d}=23\frac{1}{4}-24=\frac{93-96}{4}=\frac{-3}{4}$
$​​\text{a}_\text{n}<0$
$​​\text{a}+(\text{n}-1)​​\text{d}<0$
$24-\frac{3}{4}(​\text{n}-1)<0$
$96-3\text{n}+3<0$
$99<3\text{n}$
$33<​​\text{n}$ or $​​\text{n}>33$
$\therefore$ 34th term is 1st negetive term.

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