MCQ
Which will have enantiomer
- ✓$\begin{array}{*{20}{c}}
{C{H_3}C{H_2}CH - C{H_3}} \\
{\,|} \\
{\,\,\,Cl}
\end{array}$ - B$C{H_2}C{H_2}C{H_2}C{H_2}Cl$
- C$C{H_3}C{H_2}C{H_2}CHC{l_2}$
- DNone
$C{H_3}C{H_2} - \mathop {\mathop {\mathop {{C^ \bullet }}\limits_|^| }\limits^H - }\limits_{Cl\;} C{H_3}$
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$(a)$ $X < Y < Z$ $(b) X < Z < Y$
$(c) Y < Z < X$ $(d) Z < Y < X$
