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STD 11 - 9. Hydricarbon — JEE STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceJEESTD 11 - 9. Hydricarbon4 Marks
MCQ
Which will undergo reaction with ammoniacal $AgN{O_3}$
  • A

  • ✓
    $C{H_3} - CH = CH - C \equiv CH$
  • C
    $C{H_3} - C{H_2} - CH = CH - C{H_2} - C{H_3}$
  • D
    $C{H_2} = CH - C{H_2} - C{H_3}$
✓

Answer

Correct option: B.
$C{H_3} - CH = CH - C \equiv CH$
b
(b) $C{H_3} - CH = CH - C \equiv C - H$.   Acidic hydrogen

($H$ atom attached to triple bond) is present therefore it gives reaction with ammoniacal $AgN{O_3}$.

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