MCQ
Which would exhibit ionisation isomerism
  • A
    $\left[ {Cr{{\left( {N{H_3}} \right)}_6}} \right]C{l_3}$
  • $\left[ {Co{{\left( {N{H_3}} \right)}_5}Br} \right]S{O_4}$
  • C
    $\left[ {Cr{{(en)}_2}C{l_2}} \right]$
  • D
    $\left[ {Cr{{(en)}_3}C{l_3}} \right]$

Answer

Correct option: B.
$\left[ {Co{{\left( {N{H_3}} \right)}_5}Br} \right]S{O_4}$
b
(b) The compound which has same composition but give different ions in solution, show ionization. So $[Co{(N{H_3})_5}Br]$$SO_4^{}$ is ionization isomer.

$[Co{(N{H_3})_5}Br]S{O_4}$$ \rightleftharpoons $ ${[Co{(N{H_3})_5}Br]^{2 + }} + SO_4^{2 - }$

$[Co{(N{H_3})_5}S{O_4}]Br$$ \rightleftharpoons $ ${[Co(N{H_3})S{O_4}]^ + } + B{r^ - }$.

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