- A$\left[ {Cr{{\left( {N{H_3}} \right)}_6}} \right]C{l_3}$
- ✓$\left[ {Co{{\left( {N{H_3}} \right)}_5}Br} \right]S{O_4}$
- C$\left[ {Cr{{(en)}_2}C{l_2}} \right]$
- D$\left[ {Cr{{(en)}_3}C{l_3}} \right]$
$[Co{(N{H_3})_5}Br]S{O_4}$$ \rightleftharpoons $ ${[Co{(N{H_3})_5}Br]^{2 + }} + SO_4^{2 - }$
$[Co{(N{H_3})_5}S{O_4}]Br$$ \rightleftharpoons $ ${[Co(N{H_3})S{O_4}]^ + } + B{r^ - }$.
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$S{O_2}C{l_2}(g) \rightleftharpoons S{O_2}(g) + C{l_2}(g)$
$CO(g) + C{l_2}(g) \rightleftharpoons COC{l_2}(g)$
On adding more $SO_2$ at equilibrium what will happen ?
$A$ and $B$ are
$n - Bu -\equiv\frac{(i) n-BuLi,n - C _{5} H _{11} Cl}{(ii) Lindlar\,\, cat, H _{2}}$
$(I) \,C{H_3}CH = C{H_2} + HBr\xrightarrow{{peroxide}}$
$(II)\, C{H_3}CH = C{H_2} + HBr\xrightarrow{{CC{l_4}}}$
$(III)\, C{H_3}C{H_2}C{H_3} + B{r_2}\xrightarrow{{hv}}$
$(IV)\,C{H_3}CH = C{H_2} + B{r_2}\xrightarrow{{CC{l_4}}}$
