MCQ
While charging lead storage battery
  • A
    $PbSO _4$ on cathode is reduced to Pb
  • B
    $PbSO _4$ on anode is oxidised to $PbO _2$
  • $PbSO _4$ on anode is reduced to Pb
  • D
    $PbSO _4$ on cathode is oxidised to Pb

Answer

Correct option: C.
$PbSO _4$ on anode is reduced to Pb
$PbSO _4$ on cathode is oxidised to Pb
Explanation:
Charging: anode: $PbSO _{4( s )}+2 e ^{-} \longrightarrow Pb _{( s )}+ SO _{4( aq )}^{-2}$
Cathode:$PbSO _{4( s )}+2 H _2 O _{( l )} \longrightarrow PbO _{2( s )}+ SO _{4( aq )}^{-2}+2 e ^{-}$

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