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Electrochemistry — Chemistry STD 12 Science — Question

Gujarat BoardEnglish MediumSTD 12 ScienceChemistryElectrochemistry1 Mark
MCQ
While charging the lead storage battery $........$
  • ✓
    $\mathrm{PbSO}_4$ anode is reduced to $Pb.$
  • B
    $\mathrm{PbSO}_4$ cathode is reduced to $Pb.$
  • C
    $\mathrm{PbSO}_4$ cathode is oxidised to $Pb.$
  • D
    $\mathrm{PbSO}_4$ anode is oxidised to $\mathrm{PbO}_2$.
✓

Answer

Correct option: A.
$\mathrm{PbSO}_4$ anode is reduced to $Pb.$
While charging the lead storage battery the reaction occurring on cell is reversed and $\mathrm{PbSO}_4(s)$ on anode and cathode is converted into $Pb$ and $\mathrm{Pb0}_2$ respectively.
Hence, option $(i)$ is the correct choice The electrode reactions are as follows:
At cathode $\text{PbSO}_4(\text{s})+2\text{e}^{-}\rightarrow\text{Pb}(\text{s})+\text{SO}^{2-}_4(\text{aq})($Reduction$)$
At anode $\text{PbSO}_4(\text{s})+2\text{H}_2\text{O}\rightarrow\text{PbO}_2(\text{s})+\text{SO}^{2-}_4+4\text{H}^{+}+2\text{e}^{-}($Oxidation$)$
Overall reaction $2\text{PbSO}_4(\text{s})+2\text{H}_2\text{O}\rightarrow\text{Pb}(\text{s})+\text{PbO}_2(\text{s})+4\text{H}^+(\text{aq.})+2\text{SO}^{2-}_4(\text{aq.})$

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