MCQ
While negotiating a circular level road a cyclist has to bend by an angle θ from vertical to stay in an equilibrium is-
  • A
    $\tan \theta=\frac{r g}{r^2}$
  • $\theta=\tan ^{-1}\left(\frac{v^2}{r g}\right)$
  • C
    $\theta=\sin ^{-1}\left(\frac{r g}{r^2}\right)$
  • D
    zero

Answer

Correct option: B.
$\theta=\tan ^{-1}\left(\frac{v^2}{r g}\right)$
$\theta=\tan ^{-1}\left(\frac{v^2}{r g}\right)$

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