Question
While performing a thermodynamics experiment, a student made the following observations, $HCl + NaOH \rightarrow NaCl + H _{2} O \Delta H =-57.3\, kJ\,mol ^{-1}$

$CH _{3} COOH + NaOH \rightarrow CH _{3} COONa + H _{2} O$  $(\Delta H =-55.3\,kJ\,mol ^{-1})$ The enthalpy of ionization of $CH _{3} COOH$ as calculated by the student is $kJ mol ^{-1}$. (nearest integer)

Answer

$\Delta H _{\text {ionisation }}$ of $CH _{3} COOH =|-57.3-(-55.3)|$

$=2\,KJ / mol$

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