While working on a physics project at school physics lab, you require a $4 \,\mu F$ capacitor in a circuit across a potential difference of $1 \,kV$. Unfortunately, $4 \,\mu F$ capacitors are out of stock in your lab but $2 \,\mu F$ capacitors which can withstand a potential difference of $400 \,V$ are available in plenty. If you decide to use the $2 \,\mu F$ capacitors in place of $4 \,\mu F$ capacitor, minimum number of capacitors required are
A$16$
B$18$
C$20$
D$12$
Medium
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B$18$
b (b)
$C_{A B}=\frac{2}{3}$
Total number of benches $=\frac{{ }^2 \not 4 \times 3}{\not 2}=6$
Total number of capacitors $=6 \times 3=18$
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