- ABecause of same electronic configuration.
- BBecause of same number of electrons.
- CBecause of same number of protons.
- DBecause of same valence electrons.
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[Given : The standard enthalpy change for the reaction is $-165\, kJ\, mol ^{-1}$. The temperature in $K$ at which the reaction attains equilibrium is ... . (Nearest Integer)
Assertion $(A)$ : $\mathrm{NH}_3$ and $\mathrm{NF}_3$ molecule have pyramidal shape with a lone pair of electrons on nitrogen atom. The resultant dipole moment of $\mathrm{NH}_3$ is greater than that of $\mathrm{NF}_3$.
Reason $(R)$ : In $\mathrm{NH}_3$, the orbital dipole due to lone pair is in the same direction as the resultant dipole moment of the $\mathrm{N}-\mathrm{H}$ bonds. $\mathrm{F}$ is the most electronegative element.
In the light of the above statements, choose the correct answer from the options given below:
$BF _{3}+ NaH \stackrel{450 K }{\longrightarrow} A + NaF$
$A + NMe _{3} \rightarrow B$