Maharashtra BoardEnglish MediumSTD 12 ScienceChemistryIonic Equilibria2 Marks
Question
Why is it necessary to add $H _2 SO _4$ while preparing the solution of $CuSO _4$ ?
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Answer
$CuSO _4$ is a salt of strong acid $H _2 SO _4$ and weak base $Cu ( OH )_2 . CuSO _4$ in aqueous solution undergoes hydrolysis and forms a precipitate of $Cu ( OH )_2$ and solution becomes turbid. $CuSO _4+2 H _2 O \rightleftharpoons CU ( OH )_2 \downarrow+ H _2 SO _4$ OR $CuSO _4+4 H _2 O \rightleftharpoons Cu ( OH )_2+2 H _3 O ^{+}+ SO _4^{2-}$ When $H _2 SO _4$ is added, the hydrolysis equilibrium is shifted to left hand side and $Cu ( OH )_2$ dissolves giving clear solution.
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