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The p-Block Elements — Chemistry STD 12 Science — Question

Gujarat BoardEnglish MediumSTD 12 ScienceChemistryThe p-Block Elements2 Marks
Question
Why is $K_{a2} << K_{a1}$ for $H_2SO_4$ in water?
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Answer

$\text{H}_2\text{SO}_{4(\text{aq})}+\text{H}_2\text{O}_{(\text{I})}\rightarrow\text{H}_3\text{O}^+_{(\text{aq})}+\text{HSO}_{4(\text{aq})}^-; \ \text{K}_{\text{a}_1}>10$$\text{H}\text{SO}_{4(\text{aq})}+\text{H}_2\text{O}_{(\text{I})}\rightarrow\text{H}_3\text{O}^+_{(\text{aq})}+\text{SO}_{4(\text{aq})}^-; \ \text{K}_{\text{a}_2}=1.2\times10^{-2}$
It can be noticed that $\text{K}_{\text{a}_1}>>\text{K}_{\text{a}_2}$ This is because a neutral $H_2SO_4$ has a much higher tendency to lose a proton than the negatively charged . Thus, the former is a much stronger acid than the latter.

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