Question
Why is the $P-V$ curve for an adiabatic process steeper than that for an isothermal process ?

Answer

Adiabatic process : $PV^γ$​​​​​​​ = constant
$\therefore V^γdP + γPV^{γ-1} dV = 0$
$ \therefore V^\gamma dP +\gamma PV { }^{\gamma-1} dV =0$
$\therefore \frac{d P}{d V}=-\frac{\gamma P}{V} $
Isothermal process: $P V=$ constant
$\therefore pdV + VdP =0 \therefore \frac{d P}{d V}=\frac{P}{-V}$
$NoW _1 Y>1$
$\therefore\left|\left(\frac{d P}{d V}\right)_{\text {adiabatic }}\right|>\left|\left(\frac{d P}{d V}\right)_{\text {isotherm }}\right|$
$\therefore \frac{d P}{d V}$ is the slope of the $P - V$ curve.
$\therefore $The $P – V$ curve for an adiabatic process is steeper than that for an isothermal process.

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