Question
Why there is ozone depletion mainly over Antarctica?

Answer

This is because in other parts of the stratosphere, chlorine free radicals combine away with NO or $\mathrm{CH}_4$ but in Antarctica, the compounds formed are converted back into chlorine free radicals which deplete the ozone layer.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

Which quantity out of $\Delta_\text{r}\text{G}$ and $\Delta_\text{r}\text{G}^\ominus$ will be zero at equilibrium?
What could be temperature $15^{\circ} \mathrm{C}$ or $100^{\circ} \mathrm{C}$ for $\mathrm{K}_{\mathrm{w}}=7.5 \times 10^{-14}$. What happens to ionic product if some acid is added to it?
The hydroxides and carbonates of sodium and potassium are easily soluble in water while the corresponding salts of magnesium and calcium are sparingly soluble in water. Explain.
Indicate the number of unpaired electrons in: Si.
Determine the molecular formula of an oxide of iron in which the mass per cent of iron and oxygen are 69.9 and 30.1 respectively.
How standard electrode potential can be calculated and state its importance.
Assign oxidation number to the underlined elements in the following species:$\text{Na}\text{H}_2\text{P}\text{O}_4$
  1. How many sigma and pi bonds are there in the following molecule.
$\text{CH}_2=\text{CH}-\text{CH}_2-\text{C}\equiv\text{CH}$
  1. Which type of hybrid orbitals are used by the second carbon atom in the following molecule.
$\text{CH}\equiv\text{C}-\text{CH}_2-\text{CH}=\text{CH}_2$
At 298 K what will be the change in standard internal energy change for the given reaction:
$\mathrm{OF}_2(\mathrm{~g})+\mathrm{H}_2 \mathrm{O}(\mathrm{~g}) \rightarrow \mathrm{O}_2(\mathrm{~g})+2 \mathrm{HF}(\mathrm{~g}) \Delta \mathrm{H}=-310 \mathrm{~kJ}$
Justify that the following reactions are redox reactions:$4 \mathrm{BCl}_{3(\mathrm{~g})}+3 \mathrm{LiAlH}_{4(\mathrm{~s})} \rightarrow 2 \mathrm{~B}_2 \mathrm{H}_{6(\mathrm{~g})}+3 \mathrm{LiCl}_{(\mathrm{s})}+3 \mathrm{AlCl}_{3(\mathrm{~s})}$