MCQ
With increasing principal quantum number, the energy difference between adjacent energy levels in $H-$ atom
- ✓decreases
- Bincreases
- Cremains constant
- Ddecreases for high value of $z$ and increases for low value of $z$
$\mathrm{E}_{3}-\mathrm{E}_{2}=13.6 \times 1^{2}\left(\frac{1}{2^{2}}-\frac{1}{3^{2}}\right)=13.6 \times \frac{5}{36}$
$\mathrm{E}_{4}-\mathrm{E}_{3}=13.6 \times 1^{2}\left(\frac{1}{3^{2}}-\frac{1}{4^{2}}\right)=13.6 \times \frac{9}{144}$
Energy difference decreases as principal quantum number increases
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$I ^{-}+ ClO _3^{-}+ H _2 SO _4 \longrightarrow Cl ^{-}+ HSO _4^{-}+ I _2$
The correct statement(s) in the balanced equation is/are:
$(A)$ Stoichiometric coefficient of $HSO _4^{-}$is 6 .
$(B)$ lodide is oxidized.
$(C)$ Sulphur is reduced.
$(D)$ $H _2 O$ is one of the products.