Question
Without using trignometric tables, evaluate:
$\frac{\sec11^\circ}{\text{cosec}79^\circ}$
$\frac{\sec11^\circ}{\text{cosec}79^\circ}$
✓
Answer
$\frac{\sec11^\circ}{\text{cosec}79^\circ}$
$=\frac{\sec(90^\circ-79^\circ)}{\text{cosec}79^\circ}$
$=\frac{\text{cosec}79^\circ}{\text{cosec}79^\circ}$ $[\because\ \sec(90-\theta)=\text{cosec }\theta]$
$=1$
$=\frac{\sec(90^\circ-79^\circ)}{\text{cosec}79^\circ}$
$=\frac{\text{cosec}79^\circ}{\text{cosec}79^\circ}$ $[\because\ \sec(90-\theta)=\text{cosec }\theta]$
$=1$
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