Question
Without using trigomentric tables, prove that:
$\sec70^\circ\sin20^\circ+\cos20^\circ\text{cosec}70^\circ=2$

Answer

$\text{L.H.S}=\sec70^\circ\sin20^\circ+\cos20^\circ\text{cosec}70^\circ$
$=\sec\big(90^\circ-20^\circ\big)\sin20^\circ+\cos20^\circ\text{cosec}\big(90^\circ-20^\circ\big)$
$=\text{cosec}20^\circ.\frac{1}{\text{cosec}20^\circ}+\frac{1}{\sec20^\circ}.\sec20^\circ$
$=1+1$
$=2$
$=\text{R.H.S.}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free