Question
Without using truth table prove that :$\sim(p \vee q) \vee(\sim p \wedge q)=\sim p$
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$xy =\log y + c _{;} \frac{d y}{d x}=\frac{y^2}{1-x y}$
$\int_0^1 \frac{1}{\sqrt{3+2 x-x^2}} \cdot d x$