MCQ
Would gaseous $ HCl$ be considered as an Arrhenius acid
- AYes
- ✓No
- CNot known
- DGaseous $HCl$ does not exist
✓
Answer
Correct option: B.
No
(b)Gaseous $HCl $ does not give ${H^ + }$ but liquid $HCl $ gives ${H^ + }$ in aquous solution there for gaseous $HCl$ is not a Arrhenius acid due to covalent bonding in gaseous condition.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Which among the given acids has lowest $pKa$ value
→Mass of ethylene glycol (antifreeze) to be added to $18.6 \mathrm{~kg}$ of water to protect the freezing point at $-24^{\circ} \mathrm{C}$ is__________ $\mathrm{kg}$ (Molar mass in $\mathrm{g} \mathrm{mol}^{-1}$ for ethylene glycol $62, \mathrm{~K}_{\mathrm{f}}$ of water $=1.86 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}$ )
→For a certain reaction consider the plot of $lnk$ versus $1/T$ given in the figure. If the rate constant of this reaction at $400\,K$ is $10^{-5}\,s^{-1},$ then the rate constant at $500\,K$ is
→Assign $A, B, C, D$ from given type of reaction.
$C{r_2}O_7^{2 - } + {H^ + } + SO_3^{2 - } \longrightarrow C{r^{3 + }}\left( {aq.} \right) + SO_4^{2 - }$
→Match $List-I$ with $List-II$
→| $List-I$ | $List-II$ |
| $(A)$Glucose $+ HI$ | $(I)$ Gluconic acid |
| $(B)$Glucose $+ Br _{2}$ water | $(II)$ Glucose pentacetate |
| $(C)$Glucose $+$ acetic anhydride | $(III)$ Saccharic acid |
| $(D)$Glucose $+ HNO _{3}$ | $(IV)$ Hexane |
Choose the correct answer from the options given below.
At $1\, atm$ pressure $\Delta S = 75\, J/K \times mol$ and $\Delta H = 30\, KJ/mol$ . The temperature of reaction at equilibrium is.......$K$
→Glucose and fructose are ......................... of each other
Which of the following exhibits optical isomerism
Which of the following is Lewis acid
A fixed amount of glucose is dissolved in $100\ gm$ water to form a solution that freezes at $-0.2\,^oC$ . The solution is cooled down to $-0.25\,^oC$ . ......... $gm$ of ice would have separated.
→