Question
Write a pair of irrational numbers whose product is rational.

Answer

$(\sqrt{3}+\sqrt{2})$ and $(\sqrt{3}-\sqrt{2})$ are irrational numbers whose product is rational.
Thus, we have
$(\sqrt{3}+\sqrt{2})(\sqrt{3}-\sqrt{2})$
$=(\sqrt{3})^2-(\sqrt{2})^2$
$=3-2$
$=1$, which is a rational number.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

Find the perimeter and area of quadrilateral ABCD in which
$\begin{array}{l}AB=9 cm, AD=12 cm, BD=15 cm \\
CD=17 cm \text { and } \angle CBD=90\end{array}$.
Image
Solve for $\mathbf{x}: \frac{\log 81}{\log 27}=x$
Find $: (a + b)(a + b)(a + b)$
State, giving reason, whether the given number is rational or irrational:
(i)[$(3+\sqrt{5})$, (ii)$(-1+\sqrt{3})$, (iii )$5 \sqrt{6}$, (iv )$-\sqrt{7}$, (v )$\frac{\sqrt{6}}{4}$, (vi) $\frac{3}{\sqrt{2}}$, (vii) $(3+\sqrt{3})(3-\sqrt{3})$]
Write a pair of irrational numbers whose product is irrational.
In $\triangle ABC, D$ and $E$ are points on side $\text{AB}$ such that $\text{AD} = \text{DE} = \text{EB}.$ Through $D$ and $E,$ lines are drawn parallel to $\text{BC}$ which meet side $\text{AC}$ at points $F$ and $G$ respectively. Through $F$ and $G,$ lines are drawn parallel to $\text{AB}$ which meets side $\text{BC}$ at points $M$ and $N$ respectively. Prove that: $\text{BM} =\text{ MN} = \text{NC}.$
If $24\cos\theta = 7 \sin\theta ,$ find $\sin\theta + \cos\theta .$
A sum of $Rs. 13,500$ is invested at $16\%$ per annum compound interest for $5$ years. Calculate :
$(i)$ the interest for the first year.
$(ii)$ the amount at the end of first year.
$(iii)$ the interest for the second year, correct to the nearest rupee.
Write two irrational numbers between $\sqrt{14}$ and $\sqrt{19}$.
[Hint. $\sqrt{14}<\sqrt{15}<\sqrt{17}<\sqrt{19}$.]