Question
Write a Pythagorean triplet whose one number is $16$
✓
Answer
Here, $2m = 16$
$\therefore$ $m = \frac{{16}}{2} = 8$
$\therefore$ $m^2- 1 = 8^2- 1 = 64 - 1 = 63$
and, $m^2+ 1 = 8^2+ 1 = 64 + 1 = 65$
So, a Pythagorean triplet, whose one member is $16$ is $16, 63, 65.$
$\therefore$ $m = \frac{{16}}{2} = 8$
$\therefore$ $m^2- 1 = 8^2- 1 = 64 - 1 = 63$
and, $m^2+ 1 = 8^2+ 1 = 64 + 1 = 65$
So, a Pythagorean triplet, whose one member is $16$ is $16, 63, 65.$
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