Question
Write a Pythagorean triplet whose one number is $6$
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Answer
$2m = 6$
$\therefore m = \frac{6}{2} = 3$
$m^2– 1 = 3^2– 1 = 9 – 1 = 8$
and $m^2+ 1 = 3^2+ 1 = 9 + 1 = 10$
So, a Pythagorean triplet, whose one member is $6$, is $6, 8, 10.$
$\therefore m = \frac{6}{2} = 3$
$m^2– 1 = 3^2– 1 = 9 – 1 = 8$
and $m^2+ 1 = 3^2+ 1 = 9 + 1 = 10$
So, a Pythagorean triplet, whose one member is $6$, is $6, 8, 10.$
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