Question
Write a pythagorean triplet whose smallest member is:
$16$
$16$
✓
Answer
For every natural number $m>1,\left(2 m, m^2-1, m^2+1\right)$ is a Pythagorean triplet.
Putting $2 m=16$,
We get $m =8$
Thus, we get the triplet $(16,63,65)$.
Putting $2 m=16$,
We get $m =8$
Thus, we get the triplet $(16,63,65)$.
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