Question
Write all the four quantum numbers of the electron in the outermost shell of rubidium atom. (Atomic number = 37).

Answer

$\operatorname{Rb}(37): 1 s^2 2 s^2 2 p^6 3 s^2 3 p^6 4 s^2 3 d^{10} 4 p^6 5 s^1$
$\text{n}=5,\text{l}=0,\text{m}$ $=0,\text{s}=+\frac{1}{2}\Big(\text{either }+\frac{1}{2}\ \text{or}\ -\frac{1}{2}\Big).$

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