Question
Write an A.P. whose first term is a and common difference is d in each of the following.
$a = 6, d = – 3$
$a = 6, d = – 3$
✓
Answer
$a = 6, d = – 3$
Let $a_1 = a = 6$
Since, the common difference $d = – 3$
Using formula $a_{n + 1} = a_n + d$
Thus, $a_2 = a_1 + d = 6 + ( – 3) = 6 – 3 = 3$
$a_{3 =} a_2 + d = 3 + ( – 3) = 3 – 3 = 0$
$a_4 = a_3 + d = 0 + ( – 3) = – 3$
Hence, An A.P with common difference $– 3$ is $6, 3, 0, – 3…$
Let $a_1 = a = 6$
Since, the common difference $d = – 3$
Using formula $a_{n + 1} = a_n + d$
Thus, $a_2 = a_1 + d = 6 + ( – 3) = 6 – 3 = 3$
$a_{3 =} a_2 + d = 3 + ( – 3) = 3 – 3 = 0$
$a_4 = a_3 + d = 0 + ( – 3) = – 3$
Hence, An A.P with common difference $– 3$ is $6, 3, 0, – 3…$
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