Question
Write an A.P. whose first term is a and common difference is d in each of the following.
$a =-7, d =\frac{1}{2}$
$a =-7, d =\frac{1}{2}$
✓
Answer
$a =-7, d =\frac{1}{2}$
Let $a_1=a=-7$
Since, the common difference $d =\frac{1}{2}$
Using formula $a_{n+1}=a_n+d$
Thus, ${ }^2= a _1+ d =-7+\frac{1}{2}=\frac{-14+1}{2}=-\frac{13}{2}$
$\begin{array}{l}
a_3=a_2+d=-\frac{13}{2}+\frac{1}{2}=\frac{-13+1}{2}=-\frac{12}{2}=-6 \\
a_4=a_3+d=-6+\frac{1}{2}=\frac{-12+1}{2}=-\frac{11}{2}
\end{array}$
Hence, An A.P with common difference $\frac{1}{2}$ is $-7,-\frac{13}{2},-6,-\frac{11}{2}, \ldots .$.
Let $a_1=a=-7$
Since, the common difference $d =\frac{1}{2}$
Using formula $a_{n+1}=a_n+d$
Thus, ${ }^2= a _1+ d =-7+\frac{1}{2}=\frac{-14+1}{2}=-\frac{13}{2}$
$\begin{array}{l}
a_3=a_2+d=-\frac{13}{2}+\frac{1}{2}=\frac{-13+1}{2}=-\frac{12}{2}=-6 \\
a_4=a_3+d=-6+\frac{1}{2}=\frac{-12+1}{2}=-\frac{11}{2}
\end{array}$
Hence, An A.P with common difference $\frac{1}{2}$ is $-7,-\frac{13}{2},-6,-\frac{11}{2}, \ldots .$.
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