Question
Write an expression for Ka, for ionisation of HCN in aqueous solution. Give equation also.
$\text{K}_{\text{a}}=\frac{[\text{H}_3\text{O}^+][\text{CN}^-]}{[\text{HCN}]}$
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$2\text{PbO}+4\text{HCl}\xrightarrow{ \ \ \ \ \ \ \ }2\text{PbCl}_2+2\text{H}_2\text{O}$
$\text{PbO}_2+4\text{HCl}\xrightarrow{\ \ \ \ \ \ \ \ }\text{PbCl}_2+\text{Cl}_2+2\text{H}_2\text{O}$
Why do these compounds differ in their reactivity?