Question
Write balanced equations for:
Al + NaOH →

Answer

$2\text{Al} \ \ \ \ \ + \ \ \ \ \ \text{NaOH} \ \ \ \ \ + \ \ \ \ \ 6\text{H}_2\text{O} \ \ \ \ \ \rightarrow \ \ \ \ \ 2\text{Na}^+\big[\text{Al(OH)_4}\big]^-_{\text{(eq)}} \ \ \ \ \ + \ \ \ \ \ 3\text{H}_2 \\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{Sodium tetrahydroxoaluminate (III)}$

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