Gujarat BoardEnglish MediumSTD 12 ScienceMathsInverse Trigonometric Functions2 Marks
Question
Write cot-1 $\left(\frac{1}{\sqrt{x^{2}-1}}\right), x>1$ in the simplest form.
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Answer
Let $x$= sec $\theta$, then $\sqrt{x^{2}-1}=\sqrt{\sec ^{2} \theta-1}$ = tan $\theta$ Therefore, $\cot ^{-1} \frac{1}{\sqrt{x^{2}-1}}=\cot ^{-1}(\cot \theta)=\theta=\sec ^{-1} x$ , is the simplest form.
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